Ticket #711 (closed Bugs: invalid)
parser does not recognize in-line variable initialization
| Reported by: | caesar | Owned by: | |
|---|---|---|---|
| Priority: | 1 | Milestone: | |
| Component: | PHP Parser | Version: | 1.1.8 |
| Keywords: | Cc: |
Description
second line of the following code will produce the warning "variable $source_name may not have been initialized" while it is actually initialized just one line above:
copy ($path, $source_name = $name.'.source');
$im = new EditableImage ($souce_name);
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